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free modules造句

造句与例句手机版
  • Projective modules ( and thus free modules ) are always flat.
  • In particular, P is a finitely generated free module.
  • Stably-free modules vanish in reduced K-theory.
  • Square matrix rings arise as endomorphism rings of free modules with finite rank.
  • A finitely generated torsion-free module of a commutative PID is free.
  • It is an isomorphism if " E " is a free module of finite rank.
  • The concept and algorithms of Gr鯾ner bases have been generalized to submodules of free modules over a polynomial ring.
  • A resolution is defined as " minimal " if the image in each module morphism of free modules
  • Over a Noetherian integral domain, torsion-free modules are the modules whose only associated prime is 0.
  • Given a modules, the free object on is the vector space or free module that has as a basis.
  • It's difficult to see free modules in a sentence. 用free modules造句挺难的
  • This is equivalent to the statement that the polynomial ring is a free module over the ring of radical polynomials.
  • Geometrically, finitely generated projective modules correspond to vector bundles over affine space, and free modules to trivial vector bundles.
  • Ordinary matrices can be thought of as the coordinate representations of linear maps between vector spaces ( or free modules ).
  • A free module is a projective module, but the converse may be wrong over some rings, such as Dedekind rings.
  • This is equivalent to the statement that the ring of all polynomials is a free module over the ring of radical polynomials.
  • Another issue that arises with non-finitely generated modules is that there are torsion-free modules which are not free.
  • The relations to make the tensor product in the free module generated by the direct product can be done in similar ways.
  • On the other hand, many important properties of free abelian groups may be generalized to free modules over a principal ideal domain.
  • In algebra, a "'group ring "'is a free module and at the same time a group.
  • In contrast, no choice is needed to prove that free modules are flat, so theorems about flat modules can still apply.
  • 更多造句:  1  2  3
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